(17-2y)^2+y^2=289

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Solution for (17-2y)^2+y^2=289 equation: 



(17-2y)^2+y^2=289

We move all terms to the left:

(17-2y)^2+y^2-(289)=0

We add all the numbers together, and all the variables

y^2+(-2y+17)^2-289=0

We move all terms containing y to the left, all other terms to the right

y^2+(-2y+17)^2=289

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